In a distribution of 150 test scores, the mean grade was an 82 and the standard deviation was 8. If a student scored a 93, what would their equivalent Z score be?
A) 1.13
B) -1.38
C) 0.68
D) 1.38

Question

Quizplus · Accepted Answer

To find the Z score, we use the formula Z = (X - μ) / σ, where X is the individual score, μ is the mean, and σ is the standard deviation. Plugging in the values, we get Z = (93 - 82) / 8 = 1.38.

In a Distribution of 150 Test Scores, the Mean Grade