Given the following: heat of fusion of ice = 80.0 cal\g; specific heat of ice = 0.480 cal\g; and specific heat of water = 1.00 cal\g. Calculate the amount of heat required to melt 30.0 g of ice at 0 ° C.
A)14.4 cal
B)2.41 cal
C)80.0 cal
D)2.40 kcal

Question

Quizplus · Accepted Answer

The amount of heat required to melt 30.0 g of ice at 0 °C can be calculated using the heat of fusion of ice, which is the amount of heat needed to convert 1 g of ice at 0 °C to 1 g of water at 0 °C without changing the temperature. The heat of fusion of ice is given as 80.0 cal/g. Therefore, for 30.0 g of ice, the heat required is $30.0 \, \text{g} \times 80.0 \, \text{cal/g} = 2400 \, \text{cal}$, which is equivalent to 2.40 kcal (since 1 kcal = 1000 cal).

Given the Following: Heat of Fusion of Ice = 80