A square wave voltage varies between 0 V and 12 V. The positive pulses are 50 μ s wide and there is a 50 μ s gap between them. What is the DC average of the waveform?
A) 3 V
B) 4 V
C) 6 V
D) 9 V

Question

Quizplus · Accepted Answer

The DC average voltage of a square wave can be calculated using the formula: $V_{avg} = V_{peak} \times \frac{T_{on}}{T_{on} + T_{off}}$, where $V_{peak}$ is the peak voltage, $T_{on}$ is the duration the voltage is at $V_{peak}$, and $T_{off}$ is the duration the voltage is at 0V. Given $V_{peak} = 12V$, $T_{on} = 50 \mu s$, and $T_{off} = 50 \mu s$, the DC average is $12V \times \frac{50}{50+50} = 6V$.

A Square Wave Voltage Varies Between 0 V and 12