Consider an atom of oxygen in which the nucleus contains 8 protons and 8 neutrons.If it is doubly ionized,what is the charge of the oxygen ion and how many electrons remain in the ion?
A) Charge = +2;number of remaining electrons = 8.
B) Charge = -2;number of remaining electrons = 10.
C) Charge = +2;number of remaining electrons = 6.
D) Charge = +2;number of remaining electrons = 2.
Correct Answer:
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