Solve.
-The distance D that a spring is stretched by a hanging object varies directly as the weight W of the object. If a 12-kg object stretches a spring 57 cm, find the distance when the weight is 9-kg. Round to the nearest
Hundredths when necessary.
A) 78 cm
B) 1.89 cm
C) 4.75 cm
D) 42.75 cm

Question

Quizplus · Accepted Answer

The distance D varies directly with the weight W, so D = k*W, where k is the constant of proportionality. With a 12-kg object stretching the spring 57 cm, we find k = 57/12. For a 9-kg object, D = (57/12)*9 = 42.75 cm.

Solve. -The Distance D That a Spring Is Stretched by a a Hanging