Solve the problem.
-How many liters of a 20% alcohol solution must be mixed with 90 liters of a 80% solution to get a 40% solution?
A) 27 L
B) 18 L
C) 180 L
D) 270 L

Question

Quizplus · Accepted Answer

To solve this, we use the equation for mixture problems: (amount of first solution * its percentage + amount of second solution * its percentage) / total amount of solution = desired percentage. Let x be the amount of 20% solution needed. The equation is: (0.20x + 0.80*90) / (x + 90) = 0.40. Solving for x gives x = 180 liters.

Solve the Problem. -How Many Liters of a 20% Alcohol Solution Must Be