Solve the problem using the elimination method.
-There were 490 people at a play. The admission price was $3 for adults and $1 for children. The admission receipts were $1070. How many adults and how many children attended?
A) 290 adults and 200 children
B) 267 adults and 223 children
C) 100 adults and 390 children
D) 200 adults and 290 children

Question

Quizplus · Accepted Answer

The system of equations is: $3a + c = 1070$ and $a + c = 490$. Subtracting the second equation from the first gives $2a = 580$, so $a = 290$. Substituting $a = 290$ into $a + c = 490$ gives $c = 200$.

Solve the Problem Using the Elimination Method