Solve the problem.
-The perimeter of a rectangle is 78 m. If the width were doubled and the length were increased by 12 m, the perimeter would be 132 m. What are the length and width of the rectangle?
A) width 19 m, length 19 m
B) width 14 m, length 19 m
C) width 15 m, length 24 m
D) width 24 m, length 15 m

Question

Quizplus · Accepted Answer

The width is 15 m and the length is 24 m.The perimeter of a rectangle is given by the formula P = 2(l + w), where l is the length and w is the width.If the perimeter of a rectangle is 78 m, then we have:P = 2(l + w) = 78Solving for l + w, we get:l + w = 39If the width were doubled and the length were increased by 12 m, the new perimeter would be given by:P' = 2(l + 12 + 2w) = 132Solving for l + w, we get:l + w = 54Subtracting the first equation from the second equation, we get:12 + 2w = 15Solving for w, we get:w = 15Substituting w = 15 into the first equation, we get:l + 15 = 39Solving for l, we get:l = 24Therefore, the width of the rectangle is 15 m and the length is 24 m.

Solve the Problem. -The Perimeter of a Rectangle Is 78 M. If the M