Solve the problem.
-List all the ordered arrangements of 4 objects 1, 2, 3, and 4 choosing 3 at a time without repetition. What isP(4, 3)?
A)123, 124, 132, 134, 142, 143, 213, 214, 231, 234, 241, 243, 312, 314, 321, 324, 341, 342, 412, 413, 421, 423, 431 P(4, 3)= 24
B)123, 124, 134, 234 P(4, 3)= 4
C)123, 124, 132, 142, 143, 213, 214, 231, 241, 243, 312, 314, 321, 341, 342, 412, 413, 421, 423, 431 P(4, 3)= 20
D)111, 112, 113, 114, 121, 122, 123, 124, 131, 132, 133, 134, 141, 142, 143, 144, 211, 212, 213, 214, 221, 222, 223, 224, 231, 232, 233, 234, 241, 242, 243, 244, 311, 312, 313, 314, 321, 322, 323, 324, 331, 332, 333, 334,
341, 342, 343, 344, 411, 412, 413, 414, 421, 422, 423, 424, 431, 432, 433, 434, 441, 442, 443, 444
P(4, 3)= 64

Question

Quizplus · Accepted Answer

The permutations of 4 objects taken 3 at a time is calculated as P(4, 3) = 4! / (4-3)! = 24, matching the list provided in option A.

Solve the Problem. -List All the Ordered Arrangements of 4 Objects 1, 2