Solve the problem.
-In a chemistry class, 3 liters of a 4% silver iodide solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% solution are needed?
A)3.0 L
B)2.5 L
C)0.5 L
D)1.5 L

Question

Quizplus · Accepted Answer

Let x be the amount (in liters) of the 10% solution needed.
We can set up the following equation based on the desired concentration:
0.04(3) + 0.1x = 0.06(3+x)
0.12 + 0.1x = 0.18 + 0.06x
0.04x = 0.06
x = 1.5
Therefore, 1.5 liters of the 10% solution are needed. Let x be the number of liters of the 10% solution.
The amount of silver iodide in the 4% solution is 0.04*3 = 0.12 L.
The amount of silver iodide in the 10% solution is 0.1x.
The amount of silver iodide in the final 6% solution is 0.06(3+x).
So we can write the following equation:
0.12 + 0.1x = 0.06(3+x)
Simplifying and solving for x, we get:
0.12 + 0.1x = 0.18 + 0.06x
0.04x = 0.06
x = 1.5

Therefore, 1.5 liters of the 10% solution are needed.

Solve the Problem. -In a Chemistry Class, 3 Liters of a 4% Silver