Of all the students at a particular university, 54% prefer to have their first class at 8:00 am. If 9
Students are waiting to be advised, what is the probability that exactly 2 of them prefer to have their
First class at 8:00 am? Round to four decimal places, if necessary.
A)0.0801
B)0.0025
C)0.0458
D)0.0915

Question

Quizplus · Accepted Answer

This is a binomial probability problem where n = 9 (number of trials), k = 2 (number of successes), p = 0.54 (probability of success on a single trial), and q = 1 - p = 0.46 (probability of failure). The formula for binomial probability is P(X = k) = (n choose k) * p^k * q^(n-k). Plugging in the values: P(X = 2) = (9 choose 2) * (0.54)^2 * (0.46)^7 ≈ 0.0458.

Of All the Students at a Particular University, 54% Prefer