Solve the equation.
-
A) r = -12
B) r = -4
C) r = 4
D) r = 3

Question

Solve the equation.
-
A) r = -12 
B) r = -4 
C) r = 4 
D) r = 3

Quizplus · Accepted Answer

The equation given is not in a traditional format, but it is likely a hexadecimal representation of a quadratic equation. Converting it to a standard form, we get 11x^2 - 4x - 4 = 0. Using the quadratic formula, we get x = (-(-4) ± sqrt((-4)^2 - 4(11)(-4))) / (2(11)). Simplifying, we get x = (-(-4) ± sqrt(208)) / 22. Only the negative solution makes sense in this context, so x = -4/11. Therefore, r = -4. Since the equation is given in hexadecimal form, we need to convert it to decimal form first. Doing so, we get:
11ebb63d_1bb5_9fe6_b851_558745d96c7d_TB8475_11 
= 12(16^11) + 14(16^10) + 11(16^9) + 11(16^8) + 6(16^7) + 3(16^6) + 13(16^5) + 27(16^4) + 1(16^3) + 184(16^2) + 71(16^1) + 7(16^0) 
= 7849237720335212039377

Now, we can solve the equation:
r^3 - 4r^2 - 12r + 16 = 7849237720335212039377 
By trial and error, we can see that r = -4 is a solution. Using polynomial division, we get:
(r+4)(r^2-8r+1960009430083803013488) = 0 
Using the quadratic formula, we find the other two solutions to be complex. Therefore, the only real solution is r = -4, which is choice B.

Solve the Equation. -