Solve the problem.
-Jamil always throws loose change into a pencil holder on his desk and takes it out every two weeks. This time it is all nickels and dimes. There are 9 times as many dimes as nickels, and the value of the dimes is $9.35 more
Than the value of the nickels. How many nickels and dimes does Jamil have?
A) 11 nickels and 99 dimes
B) 10 nickels and 90 dimes
C) 12 nickels and 108 dimes
D) 99 nickels and 11 dimes

Question

Quizplus · Accepted Answer

Let the number of nickels be $n$ and the number of dimes be $d$. Given that $d = 9n$ and the value difference is $9.35, which translates to 935 cents. Since dimes are worth 10 cents and nickels 5 cents, the equation for the value difference is $10d - 5n = 935$. Substituting $d = 9n$ into the equation gives $10(9n) - 5n = 935$, simplifying to $90n - 5n = 935$, which further simplifies to $85n = 935$. Solving for $n$ gives $n = 11$, and thus $d = 9n = 99$. Therefore, Jamil has 11 nickels and 99 dimes.

Solve the Problem. -Jamil Always Throws Loose Change into a Pencil Holder on Pencil