Find the real zeros of the function, state their multiplicities if it is a number other than 1.
-$f ( x ) = 2 x ^ { 2 } - 26$
A) $x = \sqrt { 13 } , \text { mutiplicity: } 2$
B)x = -13, x = 13
C) $x = - \sqrt { 13 } , x = \sqrt { 13 }$
D)x = 13, mutiplicity: 2

Question

Quizplus · Accepted Answer

To find the real zeros of the function $f(x) = 2x^2 - 26$, we set it equal to zero and solve for $x$: $2x^2 - 26 = 0$. Simplifying, we get $x^2 = 13$, which gives us $x = \pm\sqrt{13}$, indicating two distinct real zeros, each with multiplicity 1.

Find the Real Zeros of the Function, State Their Multiplicities f(x)=2x2−26f ( x ) = 2 x ^ { 2 } - 26f(x)=2x2−26

Find the Real Zeros of the Function, State Their Multiplicities $f ( x ) = 2 x ^ { 2 } - 26$