Write the following equation in standard form. Determine the center of the ellipse.
-$16 x ^ { 2 } + 64 x + 9 y ^ { 2 } - 54 y + 1 = 0$
A)(-1, 3)
B)(-2, 3)
C)(3, -2)
D)(2, 3)

Question

Quizplus · Accepted Answer

To write the equation in standard form, complete the square for both x and y terms. The equation becomes $(16(x+2)^2)/16 + (9(y-3)^2)/9 = 1$, which simplifies to $(x+2)^2/1 + (y-3)^2/1 = 1$. The center of the ellipse is $(-2, 3)$.

Write the Following Equation in Standard Form 16x2+64x+9y2−54y+1=016 x ^ { 2 } + 64 x + 9 y ^ { 2 } - 54 y + 1 = 016x2+64x+9y2−54y+1=0

Write the Following Equation in Standard Form $16 x ^ { 2 } + 64 x + 9 y ^ { 2 } - 54 y + 1 = 0$