Solve the problem.
-An object is thrown upward with an initial velocity of 20 feet per second from the top of a 588-foot building. The height of the object at any time t can be described by the polynomial function $P ( t ) = - 16 t ^ { 2 } + 20 t + 588$ F Find
The height of the object at t = 5 seconds.
A)-300 ft
B)288 ft
C)608 ft
D)208 ft

Question

Quizplus · Accepted Answer

To find the height of the object at t = 5 seconds, substitute t = 5 into the polynomial function: $P(5) = -16(5)^2 + 20(5) + 588$. Calculate: $-16(25) + 100 + 588 = -400 + 100 + 588 = 288$ ft.

Solve the Problem P(t)=−16t2+20t+588P ( t ) = - 16 t ^ { 2 } + 20 t + 588P(t)=−16t2+20t+588

Solve the Problem $P ( t ) = - 16 t ^ { 2 } + 20 t + 588$