Solve the problem.
-The number of ways that the first-, second-, and third-place winners in a singing competition can be selected from n finalists is given by $P ( n ) = n ^ { 3 } - 3 n ^ { 2 } + 2 n$ . If there are6 finalists, how many ways can the first-, second-,
And third-place winners be selected?
A)120
B)720
C)20
D)216

Question

Quizplus · Accepted Answer

The formula for the number of ways to select the first, second, and third-place winners is $P(n) = n^3 - 3n^2 + 2n$. Substituting $n = 6$, we get $P(6) = 6^3 - 3(6)^2 + 2(6) = 216 - 108 + 12 = 120$.

Solve the Problem P(n)=n3−3n2+2nP ( n ) = n ^ { 3 } - 3 n ^ { 2 } + 2 nP(n)=n3−3n2+2n

Solve the Problem $P ( n ) = n ^ { 3 } - 3 n ^ { 2 } + 2 n$