Solve the problem.
-When a coin is dropped from a cliff of height 1800 feet, the height h of the coin from the ground (in feet)t seconds after being dropped is given by h = $- 16 t ^ { 2 }$ + 1800. How high is the coin above the ground 9 seconds
After being dropped?
A)494 ft
B)518 ft
C)504 ft
D)538 ft

Question

Quizplus · Accepted Answer

To find the height of the coin above the ground 9 seconds after being dropped, substitute $t = 9$ into the equation $h = -16t^2 + 1800$. This gives $h = -16(9)^2 + 1800 = -16(81) + 1800 = -1296 + 1800 = 504$ feet.

Solve the Problem −16t2- 16 t ^ { 2 }−16t2 + 1800 How High Is the Coin Above the Ground 9

Solve the Problem $- 16 t ^ { 2 }$ + 1800 How High Is the Coin Above the Ground 9