Solve the problem.
-Consider the rectangle below. Its area is $$x ^ { 2 } + 2 x y + y ^ { 2 }$$ and its width is 17x + 17y. Find its width, w, in terms of x and by dividing its area by its length.
A) $\frac { x + 2 x y + y } { 17 }$
B) $\frac { 17 } { x + y }$
C) $\frac { x + y } { 17 }$
D) $\frac { x ^ { 2 } + 2 x y + y ^ { 2 } } { 17 ( x + y ) }$

Question

Solve the problem.
-Consider the rectangle below. Its area is $$x ^ { 2 } + 2 x y + y ^ { 2 }$$ and its width is 17x + 17y. Find its width, w, in terms of x and by dividing its area by its length. 
A) $\frac { x + 2 x y + y } { 17 }$ 
B) $\frac { 17 } { x + y }$ 
C) $\frac { x + y } { 17 }$ 
D) $\frac { x ^ { 2 } + 2 x y + y ^ { 2 } } { 17 ( x + y ) }$

Quizplus · Accepted Answer

The Answer of Solve the problem.
-Consider the rectangle below. Its area is $$x ^ { 2 } + 2 x y + y ^ { 2 }$$ and its width is 17x + 17y. Find its width, w, in terms of x and by dividing its area by its length. 
A) $\frac { x + 2 x y + y } { 17 }$ 
B) $\frac { 17 } { x + y }$ 
C) $\frac { x + y } { 17 }$ 
D) $\frac { x ^ { 2 } + 2 x y + y ^ { 2 } } { 17 ( x + y ) }$

Solve the Problem x2+2xy+y2x ^ { 2 } + 2 x y + y ^ { 2 }x2+2xy+y2

Solve the Problem $x ^ { 2 } + 2 x y + y ^ { 2 }$