Determine the domain of the function.
-$g ( x ) = \frac { x + 6 } { x ^ { 2 } + 49 }$
A) $\{ x \mid x \neq - 7 \text { and } x \neq 7 \}$
B) $\{ x \mid x \text { is a real number } \}$
C) $\{ x \mid x \neq - 7 , x \neq 7 \text {, and } x \neq - 6 \}$
D) $\{ x \mid x \neq 0 \text { and } x \neq - 49 \}$

Question

Quizplus · Accepted Answer

The denominator $x^2 + 49$ is always positive for all real x, because squaring any real number gives a non-negative result and adding 49 ensures it's always positive. There are no values of x that make the denominator zero, so the function is defined for all real numbers.

Determine the Domain of the Function g(x)=x+6x2+49g ( x ) = \frac { x + 6 } { x ^ { 2 } + 49 }g(x)=x2+49x+6​

Determine the Domain of the Function $g ( x ) = \frac { x + 6 } { x ^ { 2 } + 49 }$