Simplify.
-$( 8 \sqrt { 2 } + 8 ) ^ { 2 }$
A) $192 - 128 \sqrt { 2 }$
B) $192 + 128 \sqrt { 2 }$
C) $136 + 128 \sqrt { 2 }$
D) $64 + 128 \sqrt { 2 }$

Question

Quizplus · Accepted Answer

To simplify $(8\sqrt{2} + 8)^2$, we use the formula $(a+b)^2 = a^2 + 2ab + b^2$. Here, $a = 8\sqrt{2}$ and $b = 8$. So, $a^2 = (8\sqrt{2})^2 = 64*2 = 128$, $2ab = 2*8\sqrt{2}*8 = 128\sqrt{2}$, and $b^2 = 8^2 = 64$. Adding these together, we get $128 + 128\sqrt{2} + 64 = 192 + 128\sqrt{2}$.

Simplify - (82+8)2( 8 \sqrt { 2 } + 8 ) ^ { 2 }(82​+8)2

Simplify
- $( 8 \sqrt { 2 } + 8 ) ^ { 2 }$