Simplify.
-$\sqrt [ 3 ] { \mathrm { p } ^ { 32 } }$
A) $\mathrm { p } \sqrt [ 3 ] { \mathrm { p } ^ { 29 } }$
B) $p ^ { 12 }$
C) $\sqrt [ 3 ] { \mathrm { p } ^ { 32 } }$
D) $p ^ { 10 } \sqrt [ 3 ] { p ^ { 2 } }$

Question

Quizplus · Accepted Answer

The expression $\sqrt [ 3 ] { \mathrm { p } ^ { 32 } }$ can be simplified by separating it into a part that has a perfect cube and a remainder. $p^{32}$ can be divided into $p^{30}$ (which is a perfect cube, as $30$ is divisible by $3$) and $p^{2}$ (the remainder). Thus, it simplifies to $p^{10} \sqrt[3]{p^2}$, because $p^{30}$ is the cube of $p^{10}$.

Simplify - p323\sqrt [ 3 ] { \mathrm { p } ^ { 32 } }3p32​

Simplify
- $\sqrt [ 3 ] { \mathrm { p } ^ { 32 } }$