Multiply.
-$2 x ^ { - 1 / 2 } \left( 3 x ^ { 5 } - x ^ { 1 / 2 } \right)$
A) $6 x ^ { 9 / 2 } - 2$
B) $6 x ^ { 9 / 2 } - 1$
C) $6 x ^ { 9 / 2 } - x$
D) $6 x ^ { 9 / 2 } - 2 x$

Question

Quizplus · Accepted Answer

When multiplying terms with exponents, you add the exponents if the bases are the same. For the first term, $2x^{-1/2} \times 3x^5 = 6x^{(-1/2) + 5} = 6x^{9/2}$. For the second term, $2x^{-1/2} \times x^{1/2} = 2x^{(-1/2) + (1/2)} = 2x^0 = 2$, since $x^0 = 1$. Therefore, the correct answer is $6x^{9/2} - 2$.

Multiply - 2x−1/2(3x5−x1/2)2 x ^ { - 1 / 2 } \left( 3 x ^ { 5 } - x ^ { 1 / 2 } \right)2x−1/2(3x5−x1/2)

Multiply
- $2 x ^ { - 1 / 2 } \left( 3 x ^ { 5 } - x ^ { 1 / 2 } \right)$