Find the vertex and axis of symmetry of the graph of the function.
-$$f ( x ) = x ^ { 2 } + 1$$
A)vertex: (0, 1); x = 0
B)vertex: (1, 0); x = 1
C)vertex: (-1, 0); x = -1
D)vertex: (0, -1); x = 0

Question

Quizplus · Accepted Answer

The vertex form of a quadratic function is $f(x) = a(x - h)^2 + k$, where $(h, k)$ is the vertex. For $f(x) = x^2 + 1$, the vertex is at $(0, 1)$ because it matches the form with $h = 0$ and $k = 1$. The axis of symmetry is $x = h$, which is $x = 0$ in this case.

Find the Vertex and Axis of Symmetry of the Graph f(x)=x2+1f ( x ) = x ^ { 2 } + 1f(x)=x2+1

Find the Vertex and Axis of Symmetry of the Graph $f ( x ) = x ^ { 2 } + 1$