Find the variance of the binomial distribution for which n = 800 and p = 0.87.
A)90.48
B)9.51
C)696
D)32.54

Question

Quizplus · Accepted Answer

The variance ($\sigma^2$) of a binomial distribution is given by the formula $\sigma^2 = np(1-p)$, where $n$ is the number of trials and $p$ is the probability of success on a single trial. Substituting $n = 800$ and $p = 0.87$, we get $\sigma^2 = 800 \times 0.87 \times (1 - 0.87) = 800 \times 0.87 \times 0.13 = 90.48$.

Find the Variance of the Binomial Distribution for Which N