The body temperatures of adults are normally distributed with a mean of 98.6° F and a standard deviation of 0.95° F. What temperature represents the 95th percentile?
A)100.16° F
B)97.04° F
C)99.82° F
D)100.46° F

Question

Quizplus · Accepted Answer

The 95th percentile is the temperature that 95% of the population is below. Using a z-score table, we can find that the z-score corresponding to the 95th percentile is 1.645. We can then use the formula z = (x - mu) / sigma to solve for x, the temperature that represents the 95th percentile:1.645 = (x - 98.6) / 0.95x = 98.6 + 1.645 * 0.95x = 100.16° F

The Body Temperatures of Adults Are Normally Distributed with a Mean