Construct a 95% confidence interval for the population mean, $\mu.$ Assume the population has a normal distribution. A sample of 20 college students had mean annual earnings of $3120 with a standard deviation of
$677.
A)($2803, $3437)
B)($1324, $1567)
C)($2135, $2567)
D)($2657, $2891)

Question

Quizplus · Accepted Answer

The 95% confidence interval for the population mean, $\mu$, can be calculated using the formula: $\bar{x} \pm z\frac{\sigma}{\sqrt{n}}$, where $\bar{x}$ is the sample mean, $z$ is the z-score corresponding to the confidence level (for 95%, $z = 1.96$), $\sigma$ is the standard deviation, and $n$ is the sample size. Plugging in the given values: $3120 \pm 1.96\frac{677}{\sqrt{20}}$ results in the interval $(2803, 3437)$.

Construct a 95% Confidence Interval for the Population Mean μ.\mu.μ. Assume the Population Has a Normal Distribution

Construct a 95% Confidence Interval for the Population Mean $\mu.$ Assume the Population Has a Normal Distribution