Find the weighted estimate, $\overline { \mathrm { p } }$ to test the claim that $\mathrm { p } _ { 1 } \mathrm { p } _ { 2 } \text {. Use } \alpha = 0.01$ Assume the samples are random and independent.
Sample statistics: $\mathrm { n } _ { 1 } = 100 , \mathrm { x } _ { 1 } = 38 , \text { and } \mathrm { n } _ { 2 } = 140 , \mathrm { x } _ { 2 } = 50$
A)0.367
B)0.523
C)0.179
D)0.633

Question

Find the weighted estimate, $\overline { \mathrm { p } }$ to test the claim that $\mathrm { p } _ { 1 } > \mathrm { p } _ { 2 } \text {. Use } \alpha = 0.01$ Assume the samples are random and independent.
Sample statistics: $\mathrm { n } _ { 1 } = 100 , \mathrm { x } _ { 1 } = 38 , \text { and } \mathrm { n } _ { 2 } = 140 , \mathrm { x } _ { 2 } = 50$
A)0.367
B)0.523
C)0.179
D)0.633

Quizplus · Accepted Answer

The weighted estimate, $\overline { \mathrm { p } }$, is calculated using the formula $\overline { \mathrm { p } } = \frac { x _ { 1 } + x _ { 2 } } { n _ { 1 } + n _ { 2 } }$. Substituting the given values, $\overline { \mathrm { p } } = \frac { 38 + 50 } { 100 + 140 } = \frac { 88 } { 240 } = 0.367$.

Find the Weighted Estimate p‾\overline { \mathrm { p } }p​

Find the Weighted Estimate $\overline { \mathrm { p } }$