Write a direct variation equation, y = kx, that satisfies the ordered pairs in the table.
-$\begin{array} { c | c | c | c | c }
\mathrm { x } & - 5 & 0 & 2 & 9 \
\hline \mathrm { y } & 15 & 0 & - 6 & - 27
\end{array}$
A) $y = \frac { 2 } { 9 } x$
B)y = -3x
C) $y = \frac { 9 } { 2 } x$
D) $y = - \frac { 1 } { 3 } x$

Question

Write a direct variation equation, y = kx, that satisfies the ordered pairs in the table.
-$\begin{array} { c | c | c | c | c } 
\mathrm { x } & - 5 & 0 & 2 & 9 \
\hline \mathrm { y } & 15 & 0 & - 6 & - 27
\end{array}$
A) $y = \frac { 2 } { 9 } x$
B)y = -3x
C) $y = \frac { 9 } { 2 } x$
D) $y = - \frac { 1 } { 3 } x$

Quizplus · Accepted Answer

The relationship between x and y in the given table is consistent with the equation y = -3x, as multiplying each x value by -3 gives the corresponding y value.

Write a Direct Variation Equation, Y = Kx, That Satisfies x−5029y150−6−27\begin{array} { c | c | c | c | c } \mathrm { x } & - 5 & 0 & 2 & 9 \\\hline \mathrm { y } & 15 & 0 & - 6 & - 27\end{array}xy​−515​00​2−6​9−27​​

Write a Direct Variation Equation, Y = Kx, That Satisfies $\begin{array} { c | c | c | c | c } \mathrm { x } & - 5 & 0 & 2 & 9 \\\hline \mathrm { y } & 15 & 0 & - 6 & - 27\end{array}$