Solve the system of equations by the addition method.
-$\left\{ \begin{array} { l }
4 x - 4 y = 10 \
20 x - 20 y = 40
\end{array} \right.$
A)(10, 40)
B) $\left( \frac { 25 } { 12 } , - \frac { 25 } { 12 } \right)$
C)(5, 4)
D)no solution

Question

Solve the system of equations by the addition method.
-$\left\{ \begin{array} { l } 
4 x - 4 y = 10 \
20 x - 20 y = 40
\end{array} \right.$
A)(10, 40)
B) $\left( \frac { 25 } { 12 } , - \frac { 25 } { 12 } \right)$
C)(5, 4)
D)no solution

Quizplus · Accepted Answer

The two equations are proportional, meaning they represent the same line. Therefore, there are infinitely many solutions, but in the context of this question, it's considered as "no solution" because there isn't a single unique solution.

Solve the System of Equations by the Addition Method {4x−4y=1020x−20y=40\left\{ \begin{array} { l } 4 x - 4 y = 10 \\20 x - 20 y = 40\end{array} \right.{4x−4y=1020x−20y=40​

Solve the System of Equations by the Addition Method $\left\{ \begin{array} { l } 4 x - 4 y = 10 \\20 x - 20 y = 40\end{array} \right.$