Solve the system of equations by the substitution method.
-$\left\{ \begin{aligned}
y & = 4 x + 2 \
3 y - 9 x & = 15
\end{aligned} \right.$
A)(14, 3)
B)(3, 14)
C)infinite number of solutions
D)no solution

Question

Quizplus · Accepted Answer

Substitute $y = 4x + 2$ into the second equation: $3(4x + 2) - 9x = 15$. Simplify to get $12x + 6 - 9x = 15$, which simplifies further to $3x = 9$, leading to $x = 3$. Substitute $x = 3$ back into the first equation to find $y = 4(3) + 2 = 14$. Therefore, the solution is $x = 3, y = 14$.

Solve the System of Equations by the Substitution Method {y=4x+23y−9x=15\left\{ \begin{aligned}y & = 4 x + 2 \\3 y - 9 x & = 15\end{aligned} \right.{y3y−9x​=4x+2=15​

Solve the System of Equations by the Substitution Method $\left\{ \begin{aligned}y & = 4 x + 2 \\3 y - 9 x & = 15\end{aligned} \right.$