Multiply.
-$\left( x ^ { 3 } + 4 \right) ^ { 2 }$
A) $x ^ { 6 } + 8 x ^ { 3 } + 16$
B) $x ^ { 6 } + 16$
C) $x ^ { 3 } + 16$
D) $16 x ^ { 6 } + 8 x ^ { 3 } + 16$

Question

Quizplus · Accepted Answer

When you square the binomial $(x^3 + 4)^2$, you use the formula $(a+b)^2 = a^2 + 2ab + b^2$, where $a = x^3$ and $b = 4$. Squaring $x^3$ gives $x^6$, squaring $4$ gives $16$, and $2ab$ gives $2 \cdot x^3 \cdot 4 = 8x^3$. Adding these together yields $x^6 + 8x^3 + 16$.

Multiply - (x3+4)2\left( x ^ { 3 } + 4 \right) ^ { 2 }(x3+4)2

Multiply
- $\left( x ^ { 3 } + 4 \right) ^ { 2 }$