Solve.
-A object is thrown upward with an initial velocity of 25 feet per second from the top of a 528-foot building. The height of the object at any time t can be described by the polynomial - $- 16 t ^ { 2 } + 25 t + 528$ . Find the height of the
Object at t = 2 seconds.
A)-14 ft
B)514 ft
C)489 ft
D)546 ft

Question

Quizplus · Accepted Answer

To find the height of the object at $t = 2$ seconds, substitute $t = 2$ into the given polynomial: $-16(2)^2 + 25(2) + 528 = -16(4) + 50 + 528 = -64 + 50 + 528 = 514$ feet.

Solve -A Object Is Thrown Upward with an Initial Velocity −16t2+25t+528- 16 t ^ { 2 } + 25 t + 528−16t2+25t+528

Solve
-A Object Is Thrown Upward with an Initial Velocity $- 16 t ^ { 2 } + 25 t + 528$