Factor the binomial completely.
-$25 a ^ { 3 } - 49 a$
A)a(5a + 7)(5a - 7)
B) $a ( 5 a - 7 ) ^ { 2 }$
C)a(25a + 1)(a - 49)
D) $\left( 5 a ^ { 2 } + 7 \right) ( 5 a - 7 )$

Question

Quizplus · Accepted Answer

The binomial $25a^3 - 49a$ can be factored by first taking out the common factor, which is $a$, resulting in $a(25a^2 - 49)$. Recognizing $25a^2$ and $49$ as perfect squares, the expression within the parentheses can be further factored using the difference of squares formula, $a^2 - b^2 = (a + b)(a - b)$, to get $a(5a + 7)(5a - 7)$.

Factor the Binomial Completely 25a3−49a25 a ^ { 3 } - 49 a25a3−49a

Factor the Binomial Completely $25 a ^ { 3 } - 49 a$