Factor the binomial completely.
-$z ^ { 2 } s ^ { 2 } - 1$
A) $( \mathrm { zs } - 1 ) ^ { 2 }$
B) $( z s + 1 ) ^ { 2 }$
C)(zs + 1)(zs - 1)
D)prime

Question

Quizplus · Accepted Answer

The given binomial $z^2s^2 - 1$ is a difference of squares, which factors as $(zs)^2 - 1^2$, and according to the difference of squares formula $a^2 - b^2 = (a + b)(a - b)$, it factors as $(zs + 1)(zs - 1)$.

Factor the Binomial Completely z2s2−1z ^ { 2 } s ^ { 2 } - 1z2s2−1

Factor the Binomial Completely $z ^ { 2 } s ^ { 2 } - 1$