Factor the trinomial completely.
-$p ^ { 2 } - 6 p q + 36 q ^ { 2 }$
A) $( p - 6 q ) ^ { 2 }$
B)(p + 6q)(p - 6q)
C) $( p + 6 q ) ^ { 2 }$
D)prime

Name: Factor the trinomial completely. -$p ^ { 2 } - 6 p q + 36 q ^ { 2 }$ A) $( p - 6 q ) ^ { 2 }$ B)(p + 6q)(p - 6q) C) $( p + 6 q ) ^ { 2 }$ D)prime
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Quizplus · Accepted Answer

The trinomial $p^2 - 6pq + 36q^2$ cannot be factored into real linear factors because the discriminant $b^2 - 4ac$ is negative, indicating it is prime over the reals.

Factor the Trinomial Completely p2−6pq+36q2p ^ { 2 } - 6 p q + 36 q ^ { 2 }p2−6pq+36q2

Factor the Trinomial Completely $p ^ { 2 } - 6 p q + 36 q ^ { 2 }$