Factor the four-term polynomial by grouping.
-$12 x ^ { 4 } - 9 x ^ { 2 } - 8 x ^ { 2 } + 6$
A) $\left( 3 x ^ { 4 } - 2 \right) ( 4 x - 3 )$
B) $\left( 3 x ^ { 2 } + 2 \right) \left( 4 x ^ { 2 } + 3 \right)$
C) $\left( 12 x ^ { 2 } + 2 \right) \left( x ^ { 2 } + 3 \right)$
D) $\left( 3 x ^ { 2 } - 2 \right) \left( 4 x ^ { 2 } - 3 \right)$

Question

Quizplus · Accepted Answer

First, group the terms: $12x^4 - 8x^2$ and $-9x^2 + 6$. Factoring out the common factors from each group gives $4x^2(3x^2 - 2) - 3(3x^2 - 2)$. Factoring by grouping gives $(3x^2 - 2)(4x^2 - 3)$.

Factor the Four-Term Polynomial by Grouping 12x4−9x2−8x2+612 x ^ { 4 } - 9 x ^ { 2 } - 8 x ^ { 2 } + 612x4−9x2−8x2+6

Factor the Four-Term Polynomial by Grouping $12 x ^ { 4 } - 9 x ^ { 2 } - 8 x ^ { 2 } + 6$