Factor out the GCF from the polynomial.
-$6 m ^ { 9 } + 16 m ^ { 6 } + 4 m ^ { 3 }$
A) $2 \left( 3 m ^ { 9 } + 8 m ^ { 6 } + 2 m ^ { 3 } \right)$
B)No common factor
C) $m ^ { 3 } \left( 6 m ^ { 6 } + 16 m ^ { 3 } + 4 \right)$
D) $2 m ^ { 3 } \left( 3 m ^ { 6 } + 8 m ^ { 3 } + 2 \right)$

Question

Quizplus · Accepted Answer

The greatest common factor (GCF) of the coefficients 6, 16, and 4 is 2, and the smallest power of $m$ that is a factor of all terms is $m^3$, making $2m^3$ the GCF. Factoring this out gives $2m^3(3m^6 + 8m^3 + 2)$.

Factor Out the GCF from the Polynomial 6m9+16m6+4m36 m ^ { 9 } + 16 m ^ { 6 } + 4 m ^ { 3 }6m9+16m6+4m3

Factor Out the GCF from the Polynomial $6 m ^ { 9 } + 16 m ^ { 6 } + 4 m ^ { 3 }$