Solve the equation for the indicated variable.
-$\frac { 1 } { a } + \frac { 1 } { b } = c$ for a
A) $a = \frac { b } { b c - 1 }$
B) $\mathrm { a } = \frac { 1 } { \mathrm { bc } }$
C) $a = \frac { 1 } { c } - b$
D) $a = b c - \frac { 1 } { b }$

Question

Quizplus · Accepted Answer

To solve for $a$, we start with the given equation $\frac { 1 } { a } + \frac { 1 } { b } = c$. We isolate $\frac { 1 } { a }$ by subtracting $\frac { 1 } { b }$ from both sides, giving $\frac { 1 } { a } = c - \frac { 1 } { b }$. To find $a$, we take the reciprocal of both sides, resulting in $a = \frac { 1 } { c - \frac { 1 } { b } }$. Simplifying further, we get $a = \frac { 1 } { \frac { b c - 1 } { b } }$, which simplifies to $a = \frac { b } { b c - 1 }$, matching choice A.

Solve the Equation for the Indicated Variable 1a+1b=c\frac { 1 } { a } + \frac { 1 } { b } = ca1​+b1​=c

Solve the Equation for the Indicated Variable $\frac { 1 } { a } + \frac { 1 } { b } = c$