Solve the inequality. Write the solution set in interval notation.
-$\frac { 3 } { 3 x - 2 } 0$ 0
A) $\left( \frac { 2 } { 3 } , \infty \right)$
B) $\left( - \infty , \frac { 2 } { 3 } \right)$
C)(0, ?)
D) $\left( - \frac { 2 } { 3 } , \infty \right)$

Question

Solve the inequality. Write the solution set in interval notation.
-$\frac { 3 } { 3 x - 2 } > 0$ 0
A) $\left( \frac { 2 } { 3 } , \infty \right)$
B) $\left( - \infty , \frac { 2 } { 3 } \right)$
C)(0, ?)
D) $\left( - \frac { 2 } { 3 } , \infty \right)$

Quizplus · Accepted Answer

The inequality $\frac { 3 } { 3 x - 2 } > 0$ holds true when the denominator $3x - 2$ is positive, which occurs for $x > \frac{2}{3}$. Thus, the solution set in interval notation is $\left( \frac { 2 } { 3 } , \infty \right)$.

Solve the Inequality 33x−2>0\frac { 3 } { 3 x - 2 } > 03x−23​>0

Solve the Inequality $\frac { 3 } { 3 x - 2 } > 0$