Solve.
-Chris rode her bicycleicycle $6 \frac { 3 } { 4 }$ miles on Tuesdmiles on Tuesday. On Thursday, she rodede $11 \frac { 1 } { 5 }$ m iles. What was her total biking distance for those two days?
A) $16 \frac { 19 } { 20 }$ mile miles
B) $6 \frac { 19 } { 20 }$ mile miles
C) $17 \frac { 19 } { 20 }$ miles mile
D) $18 \frac { 19 } { 20 }$ miles mile

Question

Quizplus · Accepted Answer

To find the total biking distance, add the distances for Tuesday and Thursday: $6 \frac{3}{4} + 11 \frac{1}{5}$. Convert mixed numbers to improper fractions: $\frac{27}{4} + \frac{56}{5}$. Find a common denominator (20), and add: $\frac{135}{20} + \frac{224}{20} = \frac{359}{20}$. Convert back to a mixed number: $17 \frac{19}{20}$.

Solve -Chris Rode Her Bicycleicycle 6346 \frac { 3 } { 4 }643​

Solve
-Chris Rode Her Bicycleicycle $6 \frac { 3 } { 4 }$