Solve.
-An ice cream cone with a 9-centimeter diameter and 15-centimeter depth is filled exactly level with the top of the cone. Approximate how much ice cream (in cubic centimeters)is in the cone. Usee $\frac { 22 } { 7 }$ for $\pi ,$
A) $954 \frac { 9 } { 14 } \text { cu cm }$
B) $318 \frac { 3 } { 14 } \mathrm { cu } \mathrm { cm }$
C) $3818 \frac { 4 } { 7 } \mathrm { cu } \mathrm { cm }$
D) $1272 \frac { 6 } { 7 } \mathrm { cu } \mathrm { cm }$

Question

Solve.
-An ice cream cone with a 9-centimeter diameter and 15-centimeter depth is filled exactly level with the top of the cone. Approximate how much ice cream (in cubic centimeters)is in the cone. Usee $\frac { 22 } { 7 }$ for $\pi ,$
A) $954 \frac { 9 } { 14 } \text { cu cm }$
B) $318 \frac { 3 } { 14 } \mathrm { cu }  \mathrm { cm }$
C) $3818 \frac { 4 } { 7 } \mathrm { cu } \mathrm { cm }$
D) $1272 \frac { 6 } { 7 } \mathrm { cu }  \mathrm { cm }$

Quizplus · Accepted Answer

The volume of a cone is given by the formula $V = \frac{1}{3}\pi r^2 h$, where $r$ is the radius and $h$ is the height. Given the diameter is 9 cm, the radius $r = \frac{9}{2} = 4.5$ cm. The height $h = 15$ cm. Using $\pi = \frac{22}{7}$, we calculate $V = \frac{1}{3} \times \frac{22}{7} \times (4.5)^2 \times 15$, which simplifies to approximately $318 \frac{3}{14}$ cubic centimeters.

Solve -An Ice Cream Cone with a 9-Centimeter Diameter and 15-Centimeter

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-An Ice Cream Cone with a 9-Centimeter Diameter and 15-Centimeter