Solve the inequality.
--5(x - 1)+ 8 $\leq$ -3(x - 0)+ 7
A) $\{ x \mid x \geq 6 \}$
B) $\{ x \mid x \geq 3 \}$
C) $\{ x \mid x \geq - 3 \}$
D) $\{ x \mid x \leq 3 \}$

Question

Quizplus · Accepted Answer

First, distribute the numbers outside the parentheses: -5x + 5 + 8 ≤ -3x + 7. Simplify both sides: -5x + 13 ≤ -3x + 7. Move the x terms to one side and the constants to the other: -5x + 3x ≤ 7 - 13, which simplifies to -2x ≤ -6. Divide by -2 (remembering to flip the inequality sign because we're dividing by a negative number): x ≥ 3.

Solve the Inequality ≤\leq≤ -3(x - 0)+ 7 A) {x∣x≥6}\{ x \mid x \geq 6 \}{x∣x≥6}

Solve the Inequality $\leq$ -3(x - 0)+ 7
A) $\{ x \mid x \geq 6 \}$