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Question 180
Solve the inequality.- 20x+45>5(3x+18) 20 x + 45 > 5 ( 3 x + 18 ) 20x+45>5(3x+18)
A) {x∣x<9}\{ x \mid x < 9 \}{x∣x<9} B) {x∣x≥9}\{ x \mid x \geq 9 \}{x∣x≥9} C) {x∣x≤9}\{ x \mid x \leq 9 \}{x∣x≤9} D) {x∣x>9}\{ x \mid x > 9 \}{x∣x>9}
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