Solve the problem.
-How much pure acid should be mixed with 6 gallons of a 50% acid solution in order to get an 80% acid solution?
A) 9 gal
B) 24 gal
C) 15 gal
D) 3 gal

Question

Quizplus · Accepted Answer

The amount of pure acid needed can be found by setting up the equation: $x + 0.50(6) = 0.80(x + 6)$, where $x$ is the amount of pure acid to be added. Solving for $x$ gives $x = 9$ gallons.

Solve the Problem. -How Much Pure Acid Should Be Mixed with 6 Gallons