The table below shows the velocities, in feet per second, of a ball that is thrown horizontally from the top of a 50 foot building and the distances, in feet, that it lands from the base of the building. Compute the linear regression equation for these data. $\begin{array} { c c }
\text { Velocity } ( \mathrm { ft } / \mathrm { sec } ) & \text { Distance } ( \mathrm { ft } ) \
15 & 48 \
25 & 80 \
29 & 100 \
33 & 95 \
38 & 112 \
40 & 130 \
48 & 150
\end{array}$
A) $y = 3.02463355 x + 3.626221498$
B) $y = 3.156886228 x + .5988023952$
C) $y = 3.073502956 x + 2.338987407$
D) $y = 3.028222013 x - 1.079962371$
E) $y = 2.944432432 x - 0.7139459459$

Question

The table below shows the velocities, in feet per second, of a ball that is thrown horizontally from the top of a 50 foot building and the distances, in feet, that it lands from the base of the building. Compute the linear regression equation for these data. $\begin{array} { c c } 
\text { Velocity } ( \mathrm { ft } / \mathrm { sec } ) & \text { Distance } ( \mathrm { ft } ) \
15 & 48 \
25 & 80 \
29 & 100 \
33 & 95 \
38 & 112 \
40 & 130 \
48 & 150
\end{array}$
A) $y = 3.02463355 x + 3.626221498$
B) $y = 3.156886228 x + .5988023952$
C) $y = 3.073502956 x + 2.338987407$
D) $y = 3.028222013 x - 1.079962371$
E) $y = 2.944432432 x - 0.7139459459$

Quizplus · Accepted Answer

The correct answer is A because the linear regression equation for the given data is y = 3.02463355 x + 3.626221498.

The Table Below Shows the Velocities, in Feet Per Second