The height in feet of a projectile with an initial velocity of 128 feet per second and an initial height of 50 feet is a function of time t, in seconds, given by $h ( t ) = - 16 t ^ { 2 } + 128 t + 50.$ Find the maximum height of the projectile.
A)409 ft
B)306 ft
C)404 ft
D)162 ft
E)498 ft

Question

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The Answer of The height in feet of a projectile with an initial velocity of 128 feet per second and an initial height of 50 feet is a function of time t, in seconds, given by $h ( t ) = - 16 t ^ { 2 } + 128 t + 50.$ Find the maximum height of the projectile.
A)409 ft
B)306 ft
C)404 ft
D)162 ft
E)498 ft

The Height in Feet of a Projectile with an Initial h(t)=−16t2+128t+50.h ( t ) = - 16 t ^ { 2 } + 128 t + 50.h(t)=−16t2+128t+50.

The Height in Feet of a Projectile with an Initial $h ( t ) = - 16 t ^ { 2 } + 128 t + 50.$