Solve the system of linear equations. $\left\{ \begin{aligned}
4 x + 3 y - z & = - 20 \
x + 3 z & = - 2 \
2 x + 4 y + 3 z & = - 20
\end{aligned} \right.$
A) $( 5,0 , - 3 )$
B) $( - 2 , - 4,0 )$
C) $( - 4,0 , - 2 )$
D) $( 0 , - 3,5 )$
E) $( - 2 , - 4,3 )$

Question

Quizplus · Accepted Answer

Substituting $x = -2$, $y = -4$, and $z = 0$ into all three equations satisfies them, confirming it as the solution.

Solve the System of Linear Equations {4x+3y−z=−20x+3z=−22x+4y+3z=−20\left\{ \begin{aligned}4 x + 3 y - z & = - 20 \\x + 3 z & = - 2 \\2 x + 4 y + 3 z & = - 20\end{aligned} \right.⎩⎨⎧​4x+3y−zx+3z2x+4y+3z​=−20=−2=−20​

Solve the System of Linear Equations $\left\{ \begin{aligned}4 x + 3 y - z & = - 20 \\x + 3 z & = - 2 \\2 x + 4 y + 3 z & = - 20\end{aligned} \right.$