Find the derivative of the function $s ( t ) = 7 x ^ { - 1 } + 4$ .
A) $s ^ { \prime } ( t ) = \frac { 7 } { x ^ { 2 } }$
B) $s ^ { \prime } ( t ) = - \frac { 7 } { x ^ { 2 } }$
C) $s ^ { \prime } ( t ) = - \frac { 7 } { x ^ { 2 } } + 4$
D) $s ^ { \prime } ( t ) = \frac { 7 } { x ^ { 2 } } + 4$
E) $s ^ { \prime } ( t ) = 7 x ^ { - 2 }$

Question

Quizplus · Accepted Answer

The derivative of $7x^{-1}$ is $-7x^{-2}$ (using the power rule for derivatives), and the derivative of a constant (4) is 0. Therefore, the correct answer is $s'(t) = -\frac{7}{x^2}$.

Find the Derivative of the Function s(t)=7x−1+4s ( t ) = 7 x ^ { - 1 } + 4s(t)=7x−1+4

Find the Derivative of the Function $s ( t ) = 7 x ^ { - 1 } + 4$