For the function given, find $f ^ { \prime } ( x )$ $f ( x ) = x ^ { 3 } - 6 x - 9$
A) $x ^ { 2 } - 6$
B) $3 x ^ { 2 } - 9$
C) $3 x ^ { 2 } - 6$
D) $3 x ^ { 3 } - 6 x$
E) $x ^ { 3 } - 6 x - 9$

Question

Quizplus · Accepted Answer

To find $f'(x)$, we differentiate $f(x) = x^3 - 6x - 9$ term by term. The derivative of $x^3$ is $3x^2$, the derivative of $-6x$ is $-6$, and the derivative of a constant ($-9$) is 0. Therefore, $f'(x) = 3x^2 - 6$.

For the Function Given, Find f′(x)f ^ { \prime } ( x )f′(x)

For the Function Given, Find $f ^ { \prime } ( x )$